Draw the major product developed in the complying with reaction of one epoxide v methoxide in methanol.

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Draw the significant product formed in the following reaction of one epoxide v acidic methanol.

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Concepts and also reasonThe three-membered cyclic ring containing 2 carbon atoms and also 1 oxygen atom is represented as one epoxide. Epoxides are also known together cyclic ethers. The opening of one epoxide complies with an attack. An epoxide ring opening depends on the form of nucleophile present.

FundamentalsIn the presence of a weak nucleophile, the nucleophile strikes an epoxide ~ above its an ext substituted site and also follows a form reaction. An instance for a weak nucleophile is

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In the visibility of a strong nucleophile, the nucleophile attacks an epoxide on a much less substituted site and follows a form reaction. An example for weak nucleophile is

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Answer:

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Explanation:Methoxide ion is a solid nucleophile and also it assaults in less substituted site. The opening of epoxide ring bring away place and also abstracts proton to type an alcohol product.

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Explanation:In this reaction, the lone pair electrons of oxygen in the epoxide experience protonation by an acid. As methanol is much less nucleophilic, it attacks the epoxide in a an ext substituted site and also opens the epoxide ring by stabilizing the cation. Then, the cation in oxygen is stabilized by the cleavage that a hydride ion.