Explanation: right here the equation because that the elevation of the ball is s(t) = -16t^2+70t+3

If we want to find the time whereby the sphere is in ~ 50 ft above the ground, we need to solve the equation:

s(t) = 50 = -16t^2+70t+3

0 = -16t^2+70t+3 - 50 = -16t^2+70t - 47

now, the services are:

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So the options are:

t1 = (-70 + 43.5)/-32 = 0.83 secs

t2 = (-70 - 43.5)/-32 = 3.55 seconds

Where we deserve to assume that t1 is as soon as the sphere is walking up, and also t2 is once the ball already reached is max allude and began to fall to the ground.

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the a 5.5 n

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