Homework statementTwo masses M1 = 6.90 kg and M2 = 3.10 kg are on a frictionless surface, enclosed by a slim string. A pressure of 48.1 N traction on M2 in ~ an angle of 31.3° native the horizontal as shown in the figure. Calculate the tension T in the string.
Homework EquationsT=ma a=g(m2/(m1+m2))
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The effort at a Solutiona=g(m1/(m1+m2))a=9.81m/s^2(3.10 kg /(6.90 kg + 3.10 kg))a=9.81m/s^2(3.10 kg/10 kg)a=9.81m/s^2(.31)a=3.0411 m/s^2T=maT=(6.90 kg)(3.0411 m/s^2)T=20.98359 N
So consider the force used on the total mass. What need to the masses accelerate? native there, isolation the system and also see the tension essential to accelerate the isolated device by that amount
So take into consideration the force applied on the total mass. What should the masses accelerate? native there, isolation the system and also see the tension necessary to accelerate the isolated mechanism by that amount
The forces that are used on the mass are F (48.1 N), gravitational force, and the normal force. Go I discover the acceleration mistakenly in my work above?
Hello Litz, welcome come PF :)Your first relevant equation is OK, noted you typical M1 because that m.But your second one originates from elsewhere and also doesn"t fit here . In this practice there is no friction through the surface, therefore the acceleration from heaviness doesn"t play a role.Instead, think about a second equation just like the very first one, but for M2. There space two pressures working top top M2 that are appropriate for this exercise. Have the right to you identify which two I mean ?
Hello Litz, welcome come PF :)Your very first relevant equation is OK, listed you mean M1 for m.But your 2nd one comes from elsewhere and also doesn"t fit right here . In this exercise there is no friction with the surface, therefore the acceleration from gravity doesn"t pat a role.Instead, consider a second equation just like the an initial one, yet for M2. There room two forces working top top M2 that are relevant for this exercise. Deserve to you distinguish which 2 I average ?
Is the revolution frictional force and also F (force indigenous the pull) what you space referring to? I have been struggling through determining forces and questions prefer the one ns posted. My TA and professor have not been beneficial when explaining the principles to me.
You perform not have actually to take into consideration the weight because its frictionless. You just need to take into consideration forces in the the direction that motionWhat perform you think is the horizontal acceleration that the totality system? think about this prior to breaking it down to look in ~ tension
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Force native the pull is definitely relevant. The various other one i meant needs to do through T. There"s a Newton law activity = -reaction: if the connecting wire pulls come the appropriate on M1 through a pressure T, climate it pulls v an equal but opposite force -T come the left on M2.The revolution frictional pressure is zero on a frictionless surface. The 2 other pressures that work on every of the 2 blocks are gravity (M1g and also M2g, respectively) working downwards, and the normal forces the surface exerts upwards. These just cancel (the blocks don"t advice in the upright direction, for this reason in the diretiction the amount of forces is zero (*) ) .So because that block 1 we have actually something through a T and also an a. These likewise appear when we create the equation because that block 2. And also there F has to present up too, yet not the complete 48.1 N. Do you understand whereI"m trying to go ?